Composite Reliability (CR) in Research

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📏 Composite Reliability (CR) in Research

Composite Reliability (CR) is a measure of internal consistency of a construct in structural equation modeling (SEM) and other latent variable models. It tells you how well a group of items (indicators) consistently reflect the same underlying construct.

It is similar to Cronbach’s alpha, but more accurate in SEM because CR:

  • Takes into account actual factor loadings of each item,

  • Does not assume equal item reliability, unlike Cronbach’s alpha.


🧮 Formula for Composite Reliability

CR=(∑λi)2(∑λi)2+∑θiCR = \frac{(\sum \lambda_i)^2}{(\sum \lambda_i)^2 + \sum \theta_i}

Where:

  • λi\lambda_i = standardized factor loading for each item,

  • θi\theta_i = error variance for each item (1 – λi2\lambda_i^2).


Interpretation of CR Values

CR Value Interpretation
≥ 0.70 Acceptable (good reliability)
0.60 – 0.70 Acceptable in exploratory research
< 0.60 Poor reliability (problematic)

Some scholars accept 0.60–0.70 as adequate for exploratory studies, but for confirmatory studies, a CR ≥ 0.70 is usually expected.


🧠 Why is Composite Reliability Important?

  • It ensures that the latent construct is measured reliably by the observed variables.

  • CR is part of construct validity testing, especially in Confirmatory Factor Analysis (CFA).

  • It is used alongside:

    • Average Variance Extracted (AVE) for convergent validity,

    • Discriminant validity tests like Fornell-Larcker criterion.


🔄 CR vs. Cronbach’s Alpha

Aspect Composite Reliability Cronbach’s Alpha
Based on factor loadings ✅ Yes ❌ No (assumes equal)
Accuracy in SEM ✅ Higher ❌ Lower
Use in CFA/SEM ✅ Preferred ❌ Less preferred

📌 Example:

You have a construct “Customer Satisfaction” measured by 4 items with factor loadings: 0.80, 0.85, 0.78, and 0.83.

  1. Compute ∑λi=0.80+0.85+0.78+0.83=3.26\sum \lambda_i = 0.80 + 0.85 + 0.78 + 0.83 = 3.26

  2. Compute ∑θi=(1−0.802)+(1−0.852)+…=0.36+0.28+0.39+0.31=1.34\sum \theta_i = (1 – 0.80^2) + (1 – 0.85^2) + … = 0.36 + 0.28 + 0.39 + 0.31 = 1.34

  3. Apply the CR formula:

CR=(3.26)2(3.26)2+1.34=10.6310.63+1.34=10.6311.97≈0.89CR = \frac{(3.26)^2}{(3.26)^2 + 1.34} = \frac{10.63}{10.63 + 1.34} = \frac{10.63}{11.97} ≈ 0.89

✅ Result: Very good composite reliability

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