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Quiz on Time and Distance for NTA UGC NET Paper 1 (27 DEC 2020)
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Question 1 of 10
1. Question
2 pointsHow many minutes Raman will take to cover a distance of 400 meters if he runs at a speed of 20 km/hr ?
Correct
⇒ Raman’s speed = 20 km/hr = 20 × 5/18 = 50/9 m/sec
⇒ 400 × 9/50 = 1⅕ minsIncorrect
⇒ Raman’s speed = 20 km/hr = 20 × 5/18 = 50/9 m/sec
⇒ 400 × 9/50 = 1⅕ mins -
Question 2 of 10
2. Question
2 pointsJohn travelled from his town to city. John went to city by bicycle at the speed of 25 km/h and came back at the speed of 4 km/h. If John took 5 hours and 48 min to complete his journey, what is the distance between town and city ?
Correct
⇒ Average speed of John = 2xy/x+y = 2 × 25 × 4 / 25 + 4= 200/29 km/h
⇒ Distance traveled = Speed × Time = 200/29 × 29/5 = 40 Km
⇒ Distance between city and town = 40/2 = 20 kmIncorrect
⇒ Average speed of John = 2xy/x+y = 2 × 25 × 4 / 25 + 4= 200/29 km/h
⇒ Distance traveled = Speed × Time = 200/29 × 29/5 = 40 Km
⇒ Distance between city and town = 40/2 = 20 km -
Question 3 of 10
3. Question
2 pointsSpeed of a train is 20 meters per second. It can cross a pole in 10 seconds. What is the length of train ?
Correct
⇒ Length of train = 20 × 10 = 200 meters
Incorrect
⇒ Length of train = 20 × 10 = 200 meters
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Question 4 of 10
4. Question
2 pointsRam walks at a speed of 12 km/h. Today the day was very hot so walked at ⅚ of his average speed. He arrived his school 10 minutes late. Find the usual time he takes to cover the distance between his school and home?
Correct
⇒ If Ram is walking at ⅚ of his usual speed that means he is taking 6/5 of using time.
⇒ 6/5 of usual time – usual time = 10 mins
⇒ 1/5 of usual time = 10 mins
⇒ Usual time = 50 minsIncorrect
⇒ If Ram is walking at ⅚ of his usual speed that means he is taking 6/5 of using time.
⇒ 6/5 of usual time – usual time = 10 mins
⇒ 1/5 of usual time = 10 mins
⇒ Usual time = 50 mins -
Question 5 of 10
5. Question
2 pointsA car running at 65 km/h takes one hour to cover a distance. If the speed is reduced by 15 km/hour then in how much time it will cover the distance ?
Correct
⇒Reduced speed = 65-15 = 50 km/h
⇒ Now car will take 65/50 × 60 mins = 78 minsIncorrect
⇒Reduced speed = 65-15 = 50 km/h
⇒ Now car will take 65/50 × 60 mins = 78 mins -
Question 6 of 10
6. Question
2 pointsIn a 100 m race A runs at a speed of 1.66 m/s. If A gives a start of 4m to B and still beats him by 12 seconds. What is the speed of B ?
Correct
⇒Time taken by A to cover 100 meters = 60 seconds
⇒ Since A gives a start of 4 seconds then time takes by B = 72 seconds
⇒ B takes 72 seconds to cover 96 meters
⇒ Speed of B = 96/72 = 1.33 m/sIncorrect
⇒Time taken by A to cover 100 meters = 60 seconds
⇒ Since A gives a start of 4 seconds then time takes by B = 72 seconds
⇒ B takes 72 seconds to cover 96 meters
⇒ Speed of B = 96/72 = 1.33 m/s -
Question 7 of 10
7. Question
2 pointsIn a kilometer race, A beats B by 100 meters. B beats C by 100 meters. By how much meters does A beat C in the same race ?
Correct
⇒ While A covers 1000 meters, B can cover 900 meters
⇒ While B covers 1000 meters, C can cover 900 meters
⇒ Lets assume that all three of them are running same race. So when B runs 900 meters, C can run 900 × 9/10 =810
⇒ So A can beat C by 190 meters.Incorrect
⇒ While A covers 1000 meters, B can cover 900 meters
⇒ While B covers 1000 meters, C can cover 900 meters
⇒ Lets assume that all three of them are running same race. So when B runs 900 meters, C can run 900 × 9/10 =810
⇒ So A can beat C by 190 meters. -
Question 8 of 10
8. Question
2 pointsWithout any stoppage a person travels a certain distance at an average speed of 42 km/hr and with stoppages he covers the same distance at an average speed of 28 km/hr. How many minutes per hour does he stop?
Correct
Incorrect
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Question 9 of 10
9. Question
2 pointsA train passes through a telegraph post in 9 seconds moving with a speed of 54 km per hour. The length of the train is
Correct
Incorrect
Length of the train = Speed of the train ✕ Time taken in crossing the post
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Question 10 of 10
10. Question
2 pointsA train 50 m long passes a platform 100 m long in 10 seconds. The speed of the train in m/sec. is
Correct
Incorrect
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